Theorem 2.1.4 (fundamental theorem of arithmetic) Factorization into primes is unique
up to order.
Proof.
We will actually prove that every integer with non-unique factorization has a proper
divisor with non-unique factorization. If there were integers with non-unique factorization,
then eventually we would be reduced to a prime with non-unique factorization, and that
would conradict the fact that it is a prime and thus has no positive divisors other than 1
and itself.
Let n be an integer with non-unique factorization:
n = p1 × p2 ×···×pr
= q1 × q2 ×···×qs ,
where the primes are not necessarily distinct, but where the second factorization is not
simply a reordering of the first. The prime q1 divides n and so it divides the product of
the pi ’s. By repeating this, there is at least one pi which is divisible by q1. If necessary,
reorder the pi ’s so that q1 divides p1. Since p1 is prime, q1 must equal p1. This says that
n = p2 × p3 ×···×pr
q1= q2 × q3 ×···×qs.
Since the factorization of n were distinct, there factorizations of n/q1 must also be distinct.
Therefore n/q1 is proper divisor of n with non-unique factorization.
where the pi are distinct primes, and the ei are positive integers. Furthermore, the
factorization is unique up to rearrangement of factors.
k , where each ei 0 and fi 0,
Theorem 2.1.5 If a = pe1
pe2 2 ···pek 1 pf2 2 ···pfk
k ,b= pf 1then
gcd(a, b)=pmin(e1 ,f1 )
k1 pmin(e2 ,f2 ) 2 ···pmin(ek ,fk )
and
k . lcm(a, b)=pmax(e1 ,f1 )
1 pmax(e2 ,f2 ) 2 ···pmax(ek ,fk )
Example 2.1.5 Let a = 4864 = 28 · 19,b= 4358 = 2 · 7 · 13 · 19. Then gcd(4864, 3458) =
2 · 19 = 38 and lcm(4864, 3458) = 28 · 7 · 13 · 19 = 442624.
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yorumlarınızın okunduğuna emin olun:) Erhan DUMAN